Finite Math Examples

7 P 2

${}_{7}P_{2}$

Step 1

Evaluate

7 P 2

${}_{7}P_{2}$ using the formula

n P r = \frac{n!}{(n - r)!}

${}_{n}P_{r} = \frac{n!}{(n - r)!}$ .

\frac{7!}{(7 - 2)!}

$\frac{7!}{(7 - 2)!}$

Step 2

Subtract

2

$2$ from

7

$7$ .

\frac{7!}{(5)!}

$\frac{7!}{(5)!}$

Step 3

Simplify

\frac{7!}{(5)!}

$\frac{7!}{(5)!}$ .

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Step 3.1

Rewrite

7!

$7!$ as

7 \cdot 6 \cdot 5!

$7 \cdot 6 \cdot 5!$ .

\frac{7 \cdot 6 \cdot 5!}{(5)!}

$\frac{7 \cdot 6 \cdot 5!}{(5)!}$

Step 3.2

Cancel the common factor of

5!

$5!$ .

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Step 3.2.1

Cancel the common factor.

$\frac{7 \cdot 6 \cdot 5!}{(5)!}$

Step 3.2.2

Divide

$7 \cdot 6$ by

$1$ .

$7 \cdot 6$

$7 \cdot 6$

Step 3.3

Multiply

$7$ by

$6$ .

$42$

$42$

${}_{7}P_{2}$

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$